what happen when sodium hydroxide react with 5% cider vinigar
When sodium hydroxide (NaOH) reacts with 5% cider vinegar (diluted acetic acid, CH3COOH), it undergoes a neutralization reaction. The reaction can be represented by the following balanced chemical equation:
NaOH + CH3COOH -> CH3COONa + H2O
In this reaction, sodium hydroxide reacts with acetic acid to form sodium acetate (CH3COONa) and water (H2O).
To understand what happens during this reaction, you need to know a few things:
1. Sodium hydroxide (NaOH) is a strong base, while acetic acid (CH3COOH) is a weak acid.
2. When a strong base reacts with a weak acid, a salt and water are formed.
3. Sodium hydroxide is a soluble compound, meaning it dissociates into sodium ions (Na+) and hydroxide ions (OH-) in water.
4. Acetic acid is also soluble in water but does not dissociate completely, meaning it partially ionizes into hydrogen ions (H+) and acetate ions (CH3COO-) when dissolved.
Now, let's look at the reaction step by step:
1. The sodium hydroxide (NaOH) dissociates in water to form sodium ions (Na+) and hydroxide ions (OH-):
NaOH -> Na+ + OH-
2. The acetic acid (CH3COOH) also ionizes in water to a small extent, releasing hydrogen ions (H+) and acetate ions (CH3COO-):
CH3COOH ⇌ H+ + CH3COO-
3. Sodium hydroxide (NaOH) reacts with acetic acid (CH3COOH). The hydroxide ions (OH-) from NaOH combine with the hydrogen ions (H+) from acetic acid to form water (H2O):
OH- + H+ -> H2O
4. The remaining ions, sodium ions (Na+) and acetate ions (CH3COO-), combine to form the salt sodium acetate (CH3COONa):
Na+ + CH3COO- -> CH3COONa
Overall, the reaction between sodium hydroxide and 5% cider vinegar results in the formation of sodium acetate and water.
To perform this reaction experimentally, you would need to measure the appropriate amounts of sodium hydroxide and 5% cider vinegar, mix them together, and observe the formation of sodium acetate and water.