A car travels directly northwards at 10m/s.it then accelarates at 2m/s^2 over a distance of 200m.calculate the car's velocity after 200m.

Vfinal^2/2 - Vo^2/2 = a*X

X = 200 m; a = 2 m/s^2; Vo = 10 m/s

Solve for Vfinal

And for full marks don't forget to add the direction.

To calculate the car's velocity after 200m, we need to consider the initial velocity and the acceleration.

Given:
Initial velocity (u) = 10 m/s
Acceleration (a) = 2 m/s^2
Distance (s) = 200 m

We can use the equation of motion:

v^2 = u^2 + 2as

where:
v = final velocity

Rearranging the equation to solve for v, we have:

v^2 = u^2 + 2as
v^2 = (10 m/s)^2 + 2 (2 m/s^2)(200 m)
v^2 = 100 m^2/s^2 + 800 m^2/s^2
v^2 = 900 m^2/s^2
v = √900 m/s
v = 30 m/s

Therefore, the car's velocity after 200m is 30 m/s.