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September 2, 2014

September 2, 2014

Posted by **-Minx-** on Wednesday, August 17, 2011 at 11:18pm.

(a).volume is increasing

V= 3/4 pie r^2

(b). surface area is increasing

A = 4 pie r^2

- MATHS help plizzz -
**Reiny**, Thursday, August 18, 2011 at 8:41amYour formula for volume is incorrect.

V = (4/3)πr^3

dV/dt = 4πr^2 dr/dt

so when r = 4

dV/dt = 4π(16)(2) = 72π cm^3/minute

A = 4πr^2

dA/dt = 8πr dr/dt

when r=4

dA/dt = 8π(4)(2) = 64π cm^2/min

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