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September 20, 2014

September 20, 2014

Posted by **Anonymous** on Wednesday, August 17, 2011 at 10:43pm.

m/s2). The mass of the car is 1354 kg. The average backward force due to air drag during

acceleration is 280 N. Find the forward force required to give the car this acceleration.

- physics -
**drwls**, Thursday, August 18, 2011 at 1:44amF(fwd) - F(bkwd) = M a

Based upon the speed change in 9.0 s, a is actually 2.98 m/s^2, not 3.0. I will use 3.0 anyway. They gave you more information that you need.

Solve for F(fwd)

F(fwd) = 280 + (1354)*(3.0) N

- physics -
**Sachin**, Thursday, August 18, 2011 at 1:13pmaccording to newton's second law;it states that

F=ma

therfore,F(force of car)-F(force of airdrag)=ma

ie:F-F=Ma

inorder to find the "F" transpond one F from left hand side to right hand side.

therfore,F=F+MA

ie:F=280+(1354)x(3.0)

F=4902.

Therfore the force needed to give the car this accelaration=4902.

- physics -
**Anonymous**, Saturday, March 8, 2014 at 9:32amNot be that person or anything... but your final calculation is incorrect... it is 4342.

- physics -
**Anonymous**, Monday, May 12, 2014 at 11:12ammy teacher book is the answer is 4.4e3

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