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November 28, 2014

November 28, 2014

Posted by **-Minx-** on Wednesday, August 17, 2011 at 10:28pm.

a.side is increasing when the side is 4 cm

b.surface area is increasing when the side is 4cm

V= x^3 A= 6x^2

- math -
**Reiny**, Wednesday, August 17, 2011 at 10:59pmdV/dt = 3x^2 dx/dt

96 = 3(4^2)dx/dt

dx/dt = 96/48 = 2 cm/second

A = 6x^2

dA/dt = 12x dx/dt

dA/dt = 12(4)(2) = 96 cm^2/sec

- math -
**-Minx-**, Wednesday, August 17, 2011 at 11:06pmA spherical balloon is being inflated and its radius is changing at the rate of 2m/minute. When the radius is 4m, find the rate at which the:

(a).volume is increasing

V= 3/4 pie r^2

(b). surface area is increasing

A = 4 pie r^2

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