Posted by Anonymous on .
Two objects are thrown simultaneously from the same height at 45° angles to the vertical with a
speed of 20 m per second; one up, the other one down. Find the difference between the heights the
objects will be at two seconds later. How are these objects moving in regards to one another?

maths/physics 
drwls,
Y1 = 20 sin45*t  (g/2)t^2
Y2 = 20 sin45*t (g/2)t^2
Y1  Y2 = 40 sin45*t = 56.6 m apart
V1 = 20 sin45  gt
V2 = 20 sin45  gt
The vertical velocity difference between them remains
V2  V1 = 40 sin 45 = 28.3 m/s
Two seconds after release, both are going down, but V2 is going down faster.