Post a New Question

maths/physics

posted by .

Two objects are thrown simultaneously from the same height at 45° angles to the vertical with a
speed of 20 m per second; one up, the other one down. Find the difference between the heights the
objects will be at two seconds later. How are these objects moving in regards to one another?

  • maths/physics -

    Y1 = 20 sin45*t - (g/2)t^2
    Y2 = -20 sin45*t -(g/2)t^2

    Y1 - Y2 = 40 sin45*t = 56.6 m apart

    V1 = 20 sin45 - gt
    V2 = -20 sin45 - gt

    The vertical velocity difference between them remains
    V2 - V1 = -40 sin 45 = -28.3 m/s

    Two seconds after release, both are going down, but V2 is going down faster.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question