Homework Help: maths/physics

Posted by Anonymous on Wednesday, August 17, 2011 at 10:09pm.

Two objects are thrown simultaneously from the same height at 45° angles to the vertical with a
speed of 20 m per second; one up, the other one down. Find the difference between the heights the
objects will be at two seconds later. How are these objects moving in regards to one another?

maths/physics - drwls, Wednesday, August 17, 2011 at 10:25pm
Y1 = 20 sin45*t - (g/2)t^2
Y2 = -20 sin45*t -(g/2)t^2

Y1 - Y2 = 40 sin45*t = 56.6 m apart

V1 = 20 sin45 - gt
V2 = -20 sin45 - gt

The vertical velocity difference between them remains
V2 - V1 = -40 sin 45 = -28.3 m/s

Two seconds after release, both are going down, but V2 is going down faster.

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