Posted by **Hailey** on Wednesday, August 17, 2011 at 8:11pm.

find y'(x) if x^y=y^x

- Calculus :) -
**Count Iblis**, Wednesday, August 17, 2011 at 10:00pm
x^y=y^x --->

y log(x) = x log(y) ----->

log(x) dy + y/x dx =

log(y) dx + x/y dy ---->

[log(x) - x/y] dy = [log(y) - y/x] dx

---->

dy/dx = [log(y) - y/x]/[log(x) - x/y]

- Calculus :) -
**Bosnian**, Thursday, August 18, 2011 at 3:27pm
Go on :

wolframalpha dot com

When page be open in rectangle type:

derivative x^y=y^x

and click option =

When you see result click option:

Show steps

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