Posted by Hailey on Wednesday, August 17, 2011 at 8:11pm.
find y'(x) if x^y=y^x

Calculus :)  Count Iblis, Wednesday, August 17, 2011 at 10:00pm
x^y=y^x >
y log(x) = x log(y) >
log(x) dy + y/x dx =
log(y) dx + x/y dy >
[log(x)  x/y] dy = [log(y)  y/x] dx
>
dy/dx = [log(y)  y/x]/[log(x)  x/y]

Calculus :)  Bosnian, Thursday, August 18, 2011 at 3:27pm
Go on :
wolframalpha dot com
When page be open in rectangle type:
derivative x^y=y^x
and click option =
When you see result click option:
Show steps
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