I think I would eliminate variables.
multiply the first equation by 2/3
multiply the second equation by 4
add the equations.
solve for abs(2-5x), you will have two solutions.
Then, put each of those solutions into the first equation, and solve for y.
Get a large blank pad on which to do this problem, and check it twice. You can finally check each solution by substitution into the second equation.
That's quite nasty for a test.
I would try the following, along the lines suggested by bobpursley
multiply the first by 2
18/|2-5x| - 8/(y^2-3y) = 10
multiply the second by 9
18/|2-5x| + 6/(y^2-3y) = 3
-14/(y^2-3y) = 7
7y^2 - 21y + 14 = 0
y^2 - 3y + 2 = 0
(y-2)(y-1) = 0
y = 2 or y = 1
I will do the y=2
If y = 2 , then
9/|2-5x| - 4/-2 = 5
9/|2-5x| = 3
3/|2-5x| = 1
|2-5x| = 3
-5x = 1
x = -1/5
-2 + 5x = 3
5x = 5
x = 1
so two pairs from that part:
(1,2) and (-1/5, 2)
you do the other two solutions, using y = 1
geography - Ms. Sue, I am not home schooled. Our teacher gives us a geography ...
chemistry help - our teacher said on our final chemistry lab test there will be ...
MATH - This is a statistics question: ***(A) Select a random sample of 30 ...
MATH - This is a statistics question: (A) Select a random sample of 30 student ...
introductory algebra - I had these problems on my test and for some reason got ...
eth - how do you think an average american's perceptions of each group are ...
teachers - Why don't most teachers at public schools let us think for ourselves...
ENGLISH - Please read for any errors. And correct them. I really would ...
science - what are the answers to the ecosystems packet for 7th grade in science...
prealgbra - solve by simulating the problem.you have a 5 -question multiple -...