Tuesday

October 21, 2014

October 21, 2014

Posted by **sheila** on Monday, August 15, 2011 at 1:52pm.

- stats.& Prob -
**MathGuru**, Monday, August 15, 2011 at 4:43pmNull hypothesis:

Ho: p = .50 -->meaning: population proportion is equal to .50

Alternative hypothesis:

Ha: p does not equal .50 -->meaning: population proportion does not equal .50

Using a formula for a binomial proportion one-sample z-test with your data included, we have:

z = (.53 - .50)/√[(.50)(.50)/1000]

Finish the calculation.

Use a z-table to find the critical values for a two-tailed test at .01 level of significance. Compare the test statistic calculated above to the critical values from the table. If the test statistic exceeds either critical value, reject the null and conclude p does not equal .50. If the test statistic does not exceed either critical value from the table, do not reject the null.

I hope this will help get you started.

**Answer this Question**

**Related Questions**

Statistics - Records show that 29% of all payments to a mail-order company are ...

com285 - Which of the following is NOT a gatekeeper? A. The HR director of a ...

Computer - Your computer is running a lot of services and applications when you ...

economics - I need to review a n example of an essay on a 700-1,050 word essay ...

english - You need to explain applications: I assumed you were describing visa ...

Chemistry - Calculate the molarity of 1.77 mol of LiCl in 30.6 L of solution. ...

software applications - what applications can use excel data?

statistics - 1. A state’s department of education reports that 12% of the high ...

Math - Records show that 29% of all payments to a mail-order company are ...

statistical applications - when is random sampling not the best approach to ...