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July 26, 2014

July 26, 2014

Posted by **christine** on Monday, August 15, 2011 at 11:10am.

Find the length and width of a rectangular lot with a perimeter of 108 meters if the length is 8 meters more than the width.

- math -
**drwls**, Monday, August 15, 2011 at 11:19amPerimeter is

2L + 2W = 108

L = W + 8

Solve by substitution.

2(W+8) + 2W = 108

4W = 92

Finish it.

- math -
**Writeacher**, Monday, August 15, 2011 at 11:51amThe rest of your posts have been removed.

Once you write up**YOUR THOUGHTS**, please re-post, and someone here will be happy to comment.

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