Post a New Question


posted by .

A hurricane wind blows across a 6.00 m times 15.0 m flat roof at a speed of 190 km/hr.
What is the pressure difference? Use 1.28 kg/m^3 for the density of air.

How much force is exerted on the roof?

If the roof cannot withstand this much force, will it "blow in" or "blow out"?


  • Math -

    Use Bernoulli's equation:
    P1+ρgh1+(1/2)ρv1² = P2+ρgh2+(1/2)ρv2²

    P1=exterior pressure
    P2=interior pressure
    v1=exterior wind velocity
    v2=interior wind velocity = 0
    h1-h2 is the negligible height differences
    ρ=density of air (1.293 kg-m^-3)

    which by neglecting ρg(h2-h1), and substituting v1=0 we get

    Suction force (blows out):
    =area*pressure difference
    =162,073 N

    The above calculation of pressure assumes:
    1. the pressure factor is -1 (which is not far for a flat roof).
    (Broken Link Removed)

    2. the STP value of ρ=1.293kg/m³ instead of 1.28 as stipulated. You will need to make adjustments to get the correct answer.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question