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March 29, 2017

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A hurricane wind blows across a 6.00 m times 15.0 m flat roof at a speed of 190 km/hr.
What is the pressure difference? Use 1.28 kg/m^3 for the density of air.

How much force is exerted on the roof?

If the roof cannot withstand this much force, will it "blow in" or "blow out"?

Help?

  • Math - ,

    Use Bernoulli's equation:
    P1+ρgh1+(1/2)ρv1² = P2+ρgh2+(1/2)ρv2²

    where
    P1=exterior pressure
    P2=interior pressure
    v1=exterior wind velocity
    v2=interior wind velocity = 0
    h1-h2 is the negligible height differences
    ρ=density of air (1.293 kg-m^-3)

    which by neglecting ρg(h2-h1), and substituting v1=0 we get
    P2-P1=(1/2)ρv1²
    v1=190km/h=52.778m/s
    ρ=1.293kg/m³=12.7N/m³

    Suction force (blows out):
    =area*pressure difference
    =6m*15m*(1/2)*1.293kg/m³*(52.8m/s)²
    =162,073 N

    The above calculation of pressure assumes:
    1. the pressure factor is -1 (which is not far for a flat roof).
    See:
    (Broken Link Removed)

    2. the STP value of ρ=1.293kg/m³ instead of 1.28 as stipulated. You will need to make adjustments to get the correct answer.

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