Posted by **Christa** on Sunday, August 14, 2011 at 9:01pm.

find the domain and range of:

the square root of 25-x^2

- math -
**MathMate**, Sunday, August 14, 2011 at 10:01pm
f(x)=√(25-x²)

For f(x) to be real, we require that the expression 25-x² be non-negative, i.e.

25-x²≥0 ....(1)

(1) is satisfied when

|x|≤5,

or x∈[-5,5] which is exactly the domain of f(x).

The range of f(x) varies from 0 when x=±5 to 5 when x=0.

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