math
posted by Christa on .
find the domain and range of:
the square root of 25x^2

f(x)=√(25x²)
For f(x) to be real, we require that the expression 25x² be nonnegative, i.e.
25x²≥0 ....(1)
(1) is satisfied when
x≤5,
or x∈[5,5] which is exactly the domain of f(x).
The range of f(x) varies from 0 when x=±5 to 5 when x=0.