On a part-time job, you are asked to bring a cylindrical iron rod of length 91.9 cm and diameter 2.70 cm from a storage room to a machinist. Calculate the weight of the rod, w.

The volume of the rod is

V = pi*(D^2/4)*L = 526 cm^3

Multiply that by the density of iron for the mass. The density is 7.86 g/cm^3.

M = 4140 g = 4.14 kg (about 9.11 pounds)

Multiply Mass (in kg) by g = 9.8 m/s^2 if you want the weight in Newtons.

A beaker of water rests on an electronic balance that reads 975.0 g. A 2.0 cm diameter solid gold copper ball attached to a string is submerged in the water, but does not touch the bottom. What's the tension in the string? What's the new balance reading?

Please, help me.

To calculate the weight of the cylindrical iron rod, we can use the formula:

Weight (w) = Volume × Density

Step 1: Find the volume of the cylindrical rod.
The formula for the volume of a cylinder is:

Volume = π × r^2 × h

Where:
- π (pi) is a mathematical constant approximately equal to 3.14159
- r is the radius of the cylinder (half of the diameter)
- h is the height or length of the cylinder

Given:
Diameter (d) = 2.70 cm
Radius (r) = d/2 = 2.70/2 = 1.35 cm = 0.0135 m (converted to meters)
Length (h) = 91.9 cm = 0.919 m (converted to meters)

Using the values above, we can calculate the volume of the rod:

Volume = π × (0.0135^2) × 0.919

Step 2: Find the density of iron.
The density of iron varies slightly depending on the type of iron used. On average, it is around 7,874 kg/m^3.

Step 3: Calculate the weight of the rod using the formula:

Weight (w) = Volume × Density

Now that we have the volume of the rod and the density of iron, we can calculate the weight (w) by substituting these values into the formula.