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September 19, 2014

September 19, 2014

Posted by **Juan** on Sunday, August 14, 2011 at 8:25pm.

sq root of (x+6) = x

- Algebra2 -
**Damon**, Sunday, August 14, 2011 at 8:36pm(x+6)^.5 = x

multiply both sides by (x+6)^.5

(x+6) = x(x+6)^.5 but (x+6)^.5 is x

so

x+6 = x^2

x^2 - x - 6 = 0

(x-3)(x+2) - 0

so x = 3 or x=-2

try x = 3

sqrt(9) = 3 sure enough

try x = -2

sqrt (4) = -2 nope, negative root does not check

so x = 3 is the answer.

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