Post a New Question

algebra 2

posted by on .

I don't know how to do this.
Which describes the number and type of roots of the equation x^3 - 4x^2 + 50x + 7 = 0?

a. 1 positive, 2 negative
b. 2 positive, 1 negative
c. 3 negative
d. 3 positive.

  • algebra 2 - ,

    Let X1, X2, X3 are roots of the equation,
    then
    X1+X2+X3=4
    X1*X2+X1*X3+X2*X3=50
    X1*X2*X3=-7
    We can choose only b.

  • algebra 2 - ,

    I don't know of any easy way to do this, so I used a website to provide a numerical solution.

    None of the choic es are correct. Two of the roots are complex. The other is negative (-0.138414..)

    Make sure you copied the problem correctly.

  • algebra 2 - ,

    There are two changes in the sign of the coefficients, so we have either 2 positive roots, or none.

    Also, by negating the odd-powered terms, there is one change of sign, so we have 1 negative root. This invalidates choices a, c and d.

    Without actually solving the equation, the choice is either
    (b), or
    "none of the above", i.e. 2 complex and one negative root (as confirmed by drwls's solution).

    Another way to see that there are 2 complex roots without solving the equation is to look at
    f'(x)=0, or
    3x^2-8x+50=0
    which does not have real roots implying no maximum nor minimum. Therefore f(x) is monotonically increasing, and therefore has only one real root.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question