Posted by jessica on Saturday, August 13, 2011 at 7:13pm.
x = u t
y = yi + vi t - 16 t^2
----------------------------
u = 1600 cos 60 = 800 ft/sec the whole time
so
x = u t
vi = 1600 sin 60 = 1386 ft/s
so
y = 96 + 1386 t -16 t^2
so
when is y = 0 ?
0 = 96 + 1386 t - 16 t^2
16 t^2 - 1386 t - 96 = 0
so
t = 86.7 or -.07 (forget negative root)
so hits ground in 86.7 seconds
do u t for range
for part d use t = x/u, u is constant
y = yi + vi (x/u) - 16 x^2/u^2
or
y = c + b x + a x^2 a parabola
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