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November 28, 2014

November 28, 2014

Posted by **AfterLife** on Saturday, August 13, 2011 at 8:11am.

My attempt bernoulli's equation says P+ 1/2 rv^2+ rgy=constant , kinematics says Vf^2 = Vi^2 + 2ax

therefore, combining them together ,, 1/2 r( Vi + sqrt 2ax )^2 + rgy.

But I think it is wrong , as I am suppose to find x in terms of h :S Help please , how can I find it?

- Physics -
**drwls**, Saturday, August 13, 2011 at 9:11amThe speed of the water leabving the hole is

V = sqrt[2 g (y-h)]

That comes from using the Bernoulli equation. y-h is the height of the water above the hole. Multiply V by the time that it takes the water to hit the ground, to get the horizontal distance travelled.

(1/2) g t^2 = y

t = sqrt(2y/g)

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