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February 27, 2015

February 27, 2015

Posted by **abu** on Friday, August 12, 2011 at 10:05pm.

of 10 m/s. Just before the ball hits the ground, its velocity will be what?

- phsical -
**Henry**, Saturday, August 13, 2011 at 7:36pmVf^2 = Vo^2 + 2gd,

d = ((Vf^2-Vo^2) / 2g) + 2,

d=((0-100) / -19.6) + 2=5.1 + 2 =7.1m

= Distance from Gnd.

Vf^2 = Vo^2 + 2gd,

Vf^2 = 0 + 2*9.8*7.1 = 139.16,

Vf = 11.8m/s.

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