phsical
posted by abu on .
A ball is tossed vertically upward from a height of 2 m with an initial velocity
of 10 m/s. Just before the ball hits the ground, its velocity will be what?

Vf^2 = Vo^2 + 2gd,
d = ((Vf^2Vo^2) / 2g) + 2,
d=((0100) / 19.6) + 2=5.1 + 2 =7.1m
= Distance from Gnd.
Vf^2 = Vo^2 + 2gd,
Vf^2 = 0 + 2*9.8*7.1 = 139.16,
Vf = 11.8m/s.