Posted by **Maya** on Friday, August 12, 2011 at 10:45am.

25 kg of ice at 0° C is combined with 4 kg of steam at 100° C. What is the final equilibrium temperature in ° C of the system? (Lf = 3.33 x 105 J/kg; Lv 2.26 x 106 J/kg, specific heat capacity of water =4186 J/(kg.K))

Question 2 options:

A) 40

B) 20

C) 60

D) 100

E) 8

- Physics _ Please help -
**drwls**, Friday, August 12, 2011 at 12:38pm
If all the ice melts, 25*Lf = 8.33*10^6 kJ is absorbed in that process. If all of the steam condenses, 4*Lv = 9.04*10^6 kJ is released in that process. There is enough steam to melt all the ice.

0.71*10^6 J are still available from condensation of remaining to raise the temperature of the melted ice. To raise all of the 25 kg to 100 C would require 1.047*10^7 kJ. So the melted water will be raised to an intermediate temperature between 0 and 100 C.

Calculate the final temperature by assuming all of the steam condenses and is lowered to final temperature Tf, releasing heat that melts all the ice and raises it to the same Tf.

25*(3.33*10^5 + 4186 Tf) = 4*(2.26*10^6 +4*(100 - Tf)]

Solve for Tf

## Answer this Question

## Related Questions

- physics - For a class demonstration, your physics instructor pours 1.16 kg of ...
- physic - For a class demonstration, your physics instructor pours 1.16 kg of ...
- Physics - If you combine 34 kg of ice at 0°C with 80 kg of steam at 100°C, what ...
- Physics - Steam of mass 11.0 g at 100°C is added to 126.7 g of ice at 0.00°C. ...
- Physics - Steam of mass 11.0 g at 100°C is added to 114.8 g of ice at 0.00°C. ...
- physics - A 1.3- block of ice is initially at a temperature of -3.5. If 6.6×105 ...
- Physics - How do i determine the rise in temperature when the passage of steam ...
- Physics - Suppose 100 g of water at 20°C is poured over a 70-g cube of ice with ...
- physics - 1100g of ice at -50C is mixed with 100g of steam at 120C. Find out how...
- Physics - A copper calorimeter can with mass .100 kg contains .160 kg of water ...

More Related Questions