Posted by **Kelly** on Thursday, August 11, 2011 at 7:38pm.

find an expression for the area under the graph of f(x)= (x^2)+x from x=2 to x=5 as a limit of a riemann sum (do not need to evaluate).

the answer i got was:

lim as x-> infinity of sigma from i=2 to n of (2+3i/n)^2+(3i/n)(3/n)

is this correct?

## Answer this Question

## Related Questions

- Calculus - The area A of the region S that lies under the graph of the ...
- Calculus - Write the Riemann sum to find the area under the graph of the ...
- calculus - consider the function f(x)= x^2/4 -6 Rn is the Riemann sum where the ...
- Calculus - Set up a Riemann sum to estimate the area under the graph of f(x) = ...
- Calculus - The following sum [(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2...
- Calculus - The following sum [(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2...
- Calculus I - Section Area: Use Riemann sums and a limit to compute the exact ...
- Calc 2 - Can you give me the step by step instructions on how to do this problem...
- Calculus - For the function f(x)=10-4(x^2), find a formula for the lower sum ...
- calculus - The question I'm having problems with is If f(x)=3x^2+7x+2, find f'(4...

More Related Questions