how do you solve this quadratic equation? tickets= -0.3x^2+12x+10
Please show the work so I can understand.
What do you mean by solve?
If you know x, you can solve for "tickets"
Were you asked to find where tickets is zero?
or
0 = -.3 x^2 + 12 x + 10 ????
If that is the case, use the quadratic equation.
Here is a quadratic equation solver:
http://www.mathsisfun.com/quadratic-equation-solver.html
To solve a quadratic equation, we can use the quadratic formula. The quadratic formula is:
x = (-b ± √(b^2 - 4ac)) / (2a)
In the given quadratic equation, tickets = -0.3x^2 + 12x + 10, the coefficients are:
a = -0.3
b = 12
c = 10
Now, let's substitute the coefficients into the quadratic formula:
x = (-12 ± √(12^2 - 4(-0.3)(10))) / (2(-0.3))
First, we simplify the inside of the square root:
x = (-12 ± √(144 - (-12))) / (-0.6)
x = (-12 ± √(144 + 12)) / (-0.6)
x = (-12 ± √156) / (-0.6)
Next, let's find the two possible solutions by solving for both the positive and negative square roots:
x₁ = (-12 + √156) / (-0.6)
x₂ = (-12 - √156) / (-0.6)
Now, we can simplify the expressions:
x₁ = (-12 + √(4 * 39)) / (-0.6)
x₁ = (-12 + 2√39) / (-0.6)
x₂ = (-12 - √(4 * 39)) / (-0.6)
x₂ = (-12 - 2√39) / (-0.6)
These are the solutions to the quadratic equation tickets = -0.3x^2 + 12x + 10.