A 2.0 kg mass swinging at the end of a 0.5 m string is travelling 3.0 m/s. What is the centripetal
force on the mass?
This and the last four physics questions were posted from the same computer.
Please use the same name when posting on this board.
Perhaps it is different names, but the questions are remarkably similar. Having answered one, I thing WLS has answered them all. Acentripetal = v^2/r
Fc=(mv^2)/r
(2.0*3.0^2)/0.5
The centripetal force is the force that keeps an object moving in a circular path. To calculate the centripetal force on the swinging mass, we can use the formula:
F = (m * v^2) / r
Where:
F = centripetal force
m = mass of the object (2.0 kg in this case)
v = velocity of the object (3.0 m/s in this case)
r = radius of the circular path (0.5 m in this case)
Plugging in the given values, we can calculate the centripetal force:
F = (2.0 kg * (3.0 m/s)^2) / 0.5 m
F = (2.0 kg * 9.0 m^2/s^2) / 0.5 m
F = 18 kg*m/s^2 / 0.5 m
F = 36 N
Therefore, the centripetal force on the mass is 36 Newtons.
You should have a textbook with this simple formula:
F(centripetal) = M V^2/R
Trying reading the assignment. It's a better way to learn than dumping off your questions here with multiple names.