A centrifuge spins a suspension at 2500 rpm in a radius of 20 cm. What is the acceleration of the
suspension?
To quaote from the Bhagavad gita, 2.22:
"As a person puts on new garments, giving up old ones, the soul similarly accepts new material bodies, giving up the old and useless ones."
You seem to be putting on one new garment a minute.
I am sorry. It was my friends we were using the same computer. It wasnot to use or misguide you. each one wanted their doubts to be answered in their name. sorry for that.
To calculate the acceleration of the suspension in the centrifuge, we can use the formula for centripetal acceleration.
The centripetal acceleration (a) is given by the formula:
a = (v^2) / r
Where:
- a is the centripetal acceleration
- v is the linear velocity of the suspension
- r is the radius of the centrifuge
In this case, we are given that the centrifuge spins at 2500 rpm, which stands for revolutions per minute. To calculate the linear velocity (v) in meters per second, we need to convert the rpm to rad/s and then multiply it by the circumference of the circle (2πr).
To convert rpm to rad/s, we can use the conversion factor:
1 rpm = 2π radians / 60 seconds
So, the linear velocity (v) can be calculated as follows:
v = (2500 rpm) * (2π radians / 60 seconds) = (2500 rpm) * (2π / 60) rad/s
Now, we can substitute the values of v and r into the formula for acceleration:
a = (v^2) / r = [(2500 rpm) * (2π / 60) rad/s]^2 / 0.2 m
Now, we can solve this equation to find the acceleration.