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March 24, 2017

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A ball is thrown up from a twelve foot platform with an initial velocity of 112 feet/second. The formula that describes the height of the ball in terms of time is: f(t) = -16t^2+112t+12.
Determine the time at which the ball reaches its maximum height. Determine the maximum height of the ball.

  • College Algebra - ,

    f'(t) = -32t + 112
    = 0 for a max of f(t)
    32t = 112
    t = 3.5

    then f(3.5) = -16(3.5^2) + 112(3.5) + 12
    = 208

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