Posted by **Tally** on Thursday, August 11, 2011 at 10:02am.

A person dives off the edge of a cliff 40m above the surface of the sea below. Assuming that air resistance is negligible, (a) How long does it dive last? (b) and with what speed does the person enter the water?

- physical science 101 -
**Henry**, Thursday, August 11, 2011 at 7:04pm
a. d = Vo*t + 0.5at^2 = 40m,

0 + 0.5 * 9.8 * t^2 = 40,

4.9t^2 = 40,

t^2 = 8.16,

t = 2.86s.

b. Vf^2 = Vo^2 + 2gd,

Vf^2 = 0 + 2 * 9.8 *40 = 784,

Vf = 28m/s.

- physical science 101 -
**Jessica**, Sunday, January 29, 2012 at 7:55pm
A) h=0.5gt^2

40=0.5(9.8)(t^2)

40=4.9t^2

t^2=8.16

t=2.86s

## Answer This Question

## Related Questions

- Physical Science - A person dives off the edge of a cliff 33m above the surface ...
- Physics - A rock falls off the edge of a cliff that is 145 m above the ground ...
- physics - A rock falls off the edge of a cliff and strikes the ground after 3.8 ...
- Physics - a stone is thrown at an angle of 30 degrees above the horizontal from ...
- physics - A person standing at the edge of a seaside cliff kicks a stone over ...
- physics - A person standing at the edge of a seaside cliff kicks a stone over ...
- physics - 9. A stone is thrown at an angle of 30° above the horizontal from the...
- math - 1. A submarine was suituated 800 feet below sea level. If it ascends 250 ...
- physics - A person standing at the edge of a seaside cliff kicks a stone over ...
- physics - A person standing at the edge of a seaside cliff kicks a stone over ...

More Related Questions