Posted by **Charles** on Thursday, August 11, 2011 at 9:50am.

I'm not sure where to start on these two problems, so any help is greatly appreciated.

1)4^x = x^2

2)5-x^2 = e^x

- calculus -
**MathMate**, Thursday, August 11, 2011 at 10:38am
I suggest a numerical approach, namely graph each side of the equation, and from the intersection point(s), do successive approximation using Newton's or other methods.

For (1), x=-0.64 approx., and for (2), there are two solutions, at x=-2.2 and x=1.3 approx.

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