A car tire has a diameter of 3 feet and is revolving at a rate of 45 rpm. At t = 0, a certain point is at height 0. What is the height of the point above the ground after 45 seconds?
Can you lead me into the right direction?
45 rpm = 2 pi radians * 45 /60 = 1.5 pi radians/second
radius = 1.5 ft
axle at 1.5 ft and up and down from there
so
y = 1.5 - 1.5 cos (1.5 pi t)
to make y = 0 at 0
at 45 s
y = 1.5 - 1.5 cos (67.5 pi)
= 2.77 ft
It really doesn't matter if the answer was posted or not. It was how it was done. I did not want the answer I just wanted to know what formula I could use so I could do it myself.
I did.
I am not sure what that means?
http://www.jiskha.com/display.cgi?id=1313012739
I already answered you below. Click on link.
But it leads me back to this same page?
I will do it again
Thank you for trying to help me but that answer does not fit any of the answer choices.
I know 45rpm translates to 3pi/2 radians. I am not sure what formula to use to figure out height.
Dara! You'd have saved yourself a lot of time if you'd posted your answer choices in your first post.
Instead, you made Damon do a lot of needless work.