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Posted by **Kathrine** on Wednesday, August 10, 2011 at 12:24am.

4t to the second power-16 over 8 over t-2 over 6

- algebra -
**Joy**, Wednesday, August 10, 2011 at 1:01amt+2/12

- algebra -
**Henry**, Wednesday, August 10, 2011 at 5:10pm((4t^2-16)/8) / (t-2)/6,

Invert and multiply:

((4t^2-16)/8) * (6/(t-2)) =

((2t-4)(2t+4)/8) * (6/(t-2)) =

(2(t-2)2(t+2)/8) * (6/(t-2) =

24(t+2) / 8 = 3(t+2).

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