Posted by **cat21** on Tuesday, August 9, 2011 at 9:44pm.

A 40 g marble moving at 2.3 m/s strikes a 29 g marble at rest. Assume the collision is perfectly elastic and the marbles collide head-on. What is the speed of the first marble immediately after the collision? What is the speed of the second marble immediately after the collision?

How do you set this up?

- Physics -
**bobpursley**, Tuesday, August 9, 2011 at 10:20pm
two equations: Conservation of momentum

M1V1+m2(0)=M1V1' + m2V2'

solve for v2' in terms of all others.

second equation: conservation of energy

M1V1^2+0=M1V1'^2 + m2V2'^2

put the v2' equation into that equation, and solve for v1'

A bit of algebra is required, get a pad of paper.

- Dont get it? -
**cat21**, Wednesday, August 10, 2011 at 9:37pm
I tried plugging the number in and it didn't work...where are the numbers supposed to be placed in the first equation?

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