Posted by **Isaac** on Tuesday, August 9, 2011 at 11:25am.

A manufacturer constructs open boxes from sheets of cardboard that are 6 inches square by cutting small squares from the corners and folding up the sides. The Research and Development Department asks you to determine the size of the square that produces a box of greatest volume. Proceed as follows. Let x be the length of a side of the square to be cut and V be the volume of the resulting box. Show that V = x(6-2x)^2 (sketched it already.)

Are there any restrictions on the value of x? Explain.

Estimate the largest volume.

- Calculus -
**Reiny**, Tuesday, August 9, 2011 at 1:50pm
This is a continuation of the question I answered for you earlier.

Since you titled it "Calculus" you should be able to finish it.

1. expand and simplify the expression for V

2. differentiate, you will have a quadratic

3. solve that quadratic by setting it equal to zero for a max of V

4. sub the value you found in 3. into the original volume equation

for the restriction, all you have to do is look at the equation for V

V of course has to be positive.

so x > 0 and x < 3 or else the base side values make no sense.

restriction on x : 0 < x < 3

- Calculus -
**Anonymous**, Wednesday, August 31, 2016 at 4:17pm
hjbsxn

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