Posted by **Anonymous** on Monday, August 8, 2011 at 5:45am.

A vampire enters a town and bites 2 person every night. The bitten 2 persons grows in to two big vampires and bites 4 persons the next night. These 4 vampires bites 6 people the next night and the 6 bites 8 and so on.......how many vampires will be there on the 5th night?

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**drwls**, Monday, August 8, 2011 at 6:47am
The "bite rate" seems to be decreasing in your example.

Fist one vampire bites two people (2 each)

Then two bite 4 (2 each)

Then 4 bite 6 (1.5 each)

Then 6 bite 8 (1.33 each)

If this trend continues, 8 bite 10, (1.25 each) on the fifth night.

What do the vampires do who are more than one day old? Retire?

It doesn't make any sense to me. You do not have a geometric progression.

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**new question**, Sunday, August 5, 2012 at 9:56pm
his qusetion was about a journey between two towns. During the start of the journey the odometer reads 39593 ( the reverse of the no is also the same) and at the end of the journey again the odometer reads a number similar to prior one....If the max speed is 90km/hr during the journey. what will be the avg speed thruout the journey?

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**Venki Dios Sonador**, Saturday, April 27, 2013 at 8:09am
41 Vampires at the end of the 5th night

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**Anonymous**, Friday, June 20, 2014 at 9:19am
how????

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**Krishna**, Saturday, July 4, 2015 at 1:55pm
I think almost everyone forgetting the first line of the problem." A VAMPIRES A TOWN AND BITES TWO PERSONS EVERY NIGHT ".

1st night= 2 (bitten by original vampire)

2nd night= 2 +4(bitten by 2 persons turned vampires previous night)

3rd night= 2 +4(bitten by 2 vampires turned previous night) +6(bitten by 4 vampires turned previous night)

(proceding in this manner...)

4th night= 2+4+6+8

5th night= 2+4+6+8+10.

Thus total vampires would be 1(original)+No.of.people bitten.

NO.of.people bitten= 2(1st night)+6(2nd night)+12(3rd night)+20(4th night) +30(5th night) = 70.

Totally, 71 vampires.

correct me if i am wrong.

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