Posted by **Alfred** on Monday, August 8, 2011 at 2:14am.

1.6 mol of Neon gas are heated from 20.0 °C to 85.2 °C at a constant pressure of 1 atm. Calculate

the work done. (R = 0.082057 L.atm/ K. mol)

- Physical Chemistry -
**drwls**, Monday, August 8, 2011 at 6:39am
Work done = (Pressure)*(Volume change)

= P(nR(T2-T1)]/P

= n*R(T2-T1)

= 1.6(0.082057 L.atm/ K. mol)*65.2K

= 8.56 L*atm

Those are inconvenient units for work, so multiply by 10^-3 m^2/L*(1.013*10^5 N/m^2/atm

I get 867 N-m (Joules)

- Physical Chemistry -
**Alfred**, Monday, August 8, 2011 at 7:42pm
so the formula is W = nR∆T

Thank you for the answer above:)

- Physical Chemistry -
**Kata**, Sunday, May 19, 2013 at 7:10pm
W=-nRT

=-(1.6)(O.O82507)(65)

=-8.53J

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