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Physical Chemistry

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1.6 mol of Neon gas are heated from 20.0 °C to 85.2 °C at a constant pressure of 1 atm. Calculate
the work done. (R = 0.082057 L.atm/ K. mol)

  • Physical Chemistry - ,

    Work done = (Pressure)*(Volume change)
    = P(nR(T2-T1)]/P
    = n*R(T2-T1)
    = 1.6(0.082057 L.atm/ K. mol)*65.2K
    = 8.56 L*atm
    Those are inconvenient units for work, so multiply by 10^-3 m^2/L*(1.013*10^5 N/m^2/atm

    I get 867 N-m (Joules)

  • Physical Chemistry - ,

    so the formula is W = nR∆T
    Thank you for the answer above:)

  • Physical Chemistry - ,

    W=-nRT
    =-(1.6)(O.O82507)(65)
    =-8.53J

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