Posted by **justin** on Sunday, August 7, 2011 at 5:32am.

. A water heater can has a power of 350 W. It is placed in a container filled with 1 litres of water with a temperature of 40 ºC. The heater is then allow to run for 1 hour. How much water will there be left in the container after 1 hour? (Specific heat capacity of water = 4200 J/kg K and specific latent heat of vaporization = 2260 000 J/kg K)

- physics -
**drwls**, Sunday, August 7, 2011 at 7:03am
1 liter of water has a mass of 1.00 kg

Energy added in one hour =

3600 s * 350 J/s = 1.26*10^6 J

Energy required to heat all of the water to 100C (the boiling point) =

1 kg*60 K*4200 J/kgK = = 2.52*10^5 J

Energy available to boil water =

1.26*10^6 - 0.252*10^6 = 0.998*10^6 J

Amount that boils away

= 0.998*10^6 J/2.26*10^6 J/kg

= 0.44 kg

The amount left will be 0.56 kg.

Notye: The units of the latent heat of vaporization should be J/kg, NOT J/kg*K

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