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September 20, 2014

September 20, 2014

Posted by **Jess** on Saturday, August 6, 2011 at 3:37pm.

After reducing i got cot= square root of 2

Am i correct?

- Precalculus -
**drwls**, Saturday, August 6, 2011 at 4:11pmYes, since

sinx cotx cscx = sqrt2 is equivalent to cotx = sqrt2

x = 45 degrees

- Precalculus -
**Anonymous**, Saturday, August 6, 2011 at 4:23pmx=arccot(sqrt2)=35 degrees (approx)

- Precalculus -
**Anonymous**, Saturday, August 6, 2011 at 4:34pm+180*n

- Precalculus -
**drwls**, Saturday, August 6, 2011 at 5:20pmMy x value was wrong. I was confusing sec with cot

x = 35.3 degrees

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