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Precalculus

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Find cot x if sin x cot x csc x = .square root 2

After reducing i got cot= square root of 2

Am i correct?

  • Precalculus - ,

    Yes, since
    sinx cotx cscx = sqrt2 is equivalent to cotx = sqrt2
    x = 45 degrees

  • Precalculus - ,

    x=arccot(sqrt2)=35 degrees (approx)

  • Precalculus - ,

    +180*n

  • Precalculus - ,

    My x value was wrong. I was confusing sec with cot

    x = 35.3 degrees

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