Homework Help: Physics Help

Posted by Cat21 on Saturday, August 6, 2011 at 3:33pm.

A small, 200 g cart is moving at 1.50 m/s on an air track when it collides with a larger, 2.00 kg cart at rest. After the collision, the small cart recoils at 0.890 m/s.
Q: What is the speed of the large cart after the collision?

How do you set this up? Would it be like (mass of small cart)/(mass of large cart)*1.50m/s? but then how do you use the 0.890 m/s?

Physics Help - drwls, Saturday, August 6, 2011 at 4:16pm
Assume linear momentum is conserved.

0.2*1.50 = 0.2*(-0.89) + 2.0*V
0.30 + 1.78 = 2.0 V
V = 1.04 m/s
Physics Help - bobpursley, Saturday, August 6, 2011 at 4:17pm
Start with the law of conservation of momentum:
initial momentum=final momentum
200(1.5)+0=200(-.890)+2000*V
solve for V.
Physics Help - bobpursley, Saturday, August 6, 2011 at 4:18pm
"Cat21". Please refrain from posting questions under different names.

Answer this Question

Related Questions

physics - A small, 300 g cart is moving at 1.90 m/s on an air track when it ...
physics - A small, 300g cart is moving at 1.60m/s on an air track when it ...
physics - A student flings a 2.3g ball of putty at a 225g cart sitting on a ...
Physics - Two air-track carts move toward one another on an air track. Cart 1 ...
Physics - Momentum - A student flings a 2.3g ball of putty at a 225g cart ...
Physics - elastic collision - A student flings a 23g ball of putty at a 225g ...
physics - A cart of mass 223 g is placed on a frictionless horizontal air track...
physics - A cart of mass 223 g is placed on a frictionless horizontal air track...
physics - A cart of mass 223 g is placed on a frictionless horizontal air track...
physics-momentum HELP PLEASE tesst in two days - A student flings a 2.3g ball of...

For Further Reading

First Name:
School Subject:
Answer: