Calculate the magnetic flux density in air at a point 15mm from a long straight wire carrying a current of 100A
B = (mu-o)*I/(2*pi*R) Tesla, where
mu_o = 4 pi*10^-7 Weber/Amp*meter
I = 100 A
R = 0.015 m
= 2*10^-7*100/0.015 = 0.00133 T
The free space permeability, mu_o, can be used for air
To calculate the magnetic flux density (B) at a point near a long straight wire carrying a current, we can use the formula known as Ampere's Law.
Ampere's Law states that the magnetic field (B) around a long straight wire is directly proportional to the current (I) and inversely proportional to the distance (r) from the wire.
The formula for calculating the magnetic field is:
B = (μ₀ * I) / (2π * r)
Where:
B = Magnetic Flux Density
μ₀ = Permeability of free space (μ₀ ≈ 4π x 10⁻⁷ Tm/A)
I = Current flowing through the wire in Amperes
r = Distance from the wire in meters
Let's substitute the given values into the formula:
I = 100A
r = 15mm = 0.015m (converted to meters)
Now, we can calculate the magnetic flux density:
B = (4π x 10⁻⁷ Tm/A * 100A) / (2π * 0.015m)
Simplifying the equation, we get:
B = (4π x 10⁻⁷ T * m) / (0.03 m)
B = 1.33 x 10⁻⁵ T
Therefore, the magnetic flux density at a point 15mm away from the wire carrying a current of 100A is approximately 1.33 x 10⁻⁵ Tesla (T).