Posted by **Janine** on Friday, August 5, 2011 at 7:24am.

determine the amplitude and period of each function.

1) y = 3sin (2x-pi/2)

2) y = -3sin2 (x-pi/4)

3) y = 2cos (2x+pi)

4) y = -2cos2 (x+pi/2)

- Math Trigonometry -
**Reiny**, Friday, August 5, 2011 at 7:43am
for y = a sin (kx) or y = a cos (kx)

the amplitude is |a| and the period is 2π/k

so for the first one, y = 3 sin (2x - π/2)

amplitude is 3 , period = 2π/2 = π

do the others the same way.

- Math Trigonometry -
**drwls**, Friday, August 5, 2011 at 7:48am
The amplitude is the coefficient in front of the trig term. Forget whether it is + or -.

Let a be the number in front of the x.

a = 2 pi/P, so

P = 2 pi/a

For question 1), the amplitude is 3 and the period is pi

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