Posted by **Kathy** on Thursday, August 4, 2011 at 10:36pm.

The asymptotes of the function g(x)=(x+2)/(x^2+2x-3) are...

a. vertical: x=-2, x=1; horizontal: y=0

b. vertical: x=-3, x=1; horizontal: y=0

c. vertical: x=-2, x=-3; horizontal: y=0

d. vertical: x=-3, x=1; horizontal: none

- Math -
**Reiny**, Thursday, August 4, 2011 at 10:43pm
vertical asymptotes exist when the denominator is zero, so

x^2 + 2x - 3 = 0

(x+3)(x-1) = 0

x = -3, x = 1

as x ---> infinity , g(x) = large/even larger ---> 0

y = 0

so it looks like b)

- Math -
**Kathy**, Thursday, August 4, 2011 at 10:44pm
THANKS!

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