Posted by **Anonymous** on Thursday, August 4, 2011 at 10:25pm.

a conical tank is 15 feet deep and has an open top whose radius is 15 feet. Assume that starting at t = 0 water is added to the tank at a rate of pi ft^3/hr, and water evaporates from the tank at a rate proportional to the suface area with the constant of proportionality being 0.01. The tank is assumed to be empty at time t = 0. Let V and h represent the volume and depth of water in the tank.

solve the equation dh/dt = (1-0.01h^2)/h^2

## Answer this Question

## Related Questions

- Math - A conical water tank with vertex down has a radius of 10 feet at the top ...
- Calculus (math) - A conical water tank with vertex down has a radius of 12 feet ...
- math - calc - A conical water tank with vertex down has a radius of 12 feet at ...
- math - calc - A conical water tank with vertex down has a radius of 12 feet at ...
- calculus - A conical water tank with vertex down has a radius of 12 feet at the ...
- calculus - A conical tank( with vertex down) is 10 feet across the top and 18 ...
- calculus-rate problem - A conical tank (with vertex down) is 10 feet acros the ...
- Math - A conical water tank with vertex down has a radius of 10 feet at the top ...
- Math - A conical water tank with vertex down has a radius of 10 feet at the top ...
- cal - A conical tank (with vertex down) is 12 feet across the top and 18 feet ...

More Related Questions