Posted by **Anonymous** on Thursday, August 4, 2011 at 10:25pm.

a conical tank is 15 feet deep and has an open top whose radius is 15 feet. Assume that starting at t = 0 water is added to the tank at a rate of pi ft^3/hr, and water evaporates from the tank at a rate proportional to the suface area with the constant of proportionality being 0.01. The tank is assumed to be empty at time t = 0. Let V and h represent the volume and depth of water in the tank.

solve the equation dh/dt = (1-0.01h^2)/h^2

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