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July 25, 2014

July 25, 2014

Posted by **kusum** on Thursday, August 4, 2011 at 1:28am.

- maths -
**Reiny**, Thursday, August 4, 2011 at 7:39amlet f(x) = x^3 + mx^2 + nx + 6

given:

f(2) = 0

= 8 + 4m + 2n + 6 = 0 ---> 2m + n = -7

given: f(3) = 3

= 27 + 9m + 3n + 6 = 3 --- 3m + n = -10

subtract the two equations to get : m = -3

sub that into 2m+n=-7

-6 + n = -7

n = -1

m= -3, n = -1

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