How many gtams of potassium bromide(KBr), could be recovered by evaoportating 650.g of 15 percent KBr solution to dryness?
Can you explain how to solve this?
15% KBr soln means 15 g KBr in 100 g soln. So all you need to do is to calculate the number of grams KBr in 650 g soln. That is simply
15 x (650/100) = ??