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August 23, 2014

August 23, 2014

Posted by **ROCKY** on Wednesday, August 3, 2011 at 7:13pm.

[3/ua^2)^-4

- intermediate algebra -
**Henry**, Thursday, August 4, 2011 at 4:38pm(3/ua^2)^-4 =

1 / (3/ua^2)^4 =

1 / (81/u^4a^8) =

1 * (u^4a^8/81) =

(u^4a^8) / 81.

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