Write the slope-intercept equation for the line that passes through (2, -4) and has slope -7/2.
its easy just use the equation y=mx+b
-4=2(-7/2)+b
multiply 2 times -7/2 by adding a 1 to the bottom.
then u get -7/2
then u take the -7/2 and change it to positive and to the other side with the -4 then u subtract because positive and negative make negative. and u get 3/2
thanks pankrasia
To find the slope-intercept equation for a line, we need two pieces of information: the slope of the line and a point that lies on the line.
In this case, we are given the slope of the line, which is -7/2, and the point (2, -4) that lies on the line.
The slope-intercept equation is given by the formula: y = mx + b
where m represents the slope and b represents the y-intercept.
Step 1: Plug in the given slope
We are given that the slope is -7/2, so we can substitute -7/2 for m in the equation:
y = (-7/2)x + b
Step 2: Substituting the coordinates of the given point
To determine the value of b, we can substitute the x and y coordinates of the given point (2, -4) into the equation.
Plugging in x = 2 and y = -4, we have:
-4 = (-7/2)(2) + b
Step 3: Solve for b
Now solve the equation for b to find the y-intercept.
-4 = (-7/2)(2) + b
-4 = -7 + b
To isolate b, add 7 to both sides of the equation:
-4 + 7 = -7 + b + 7
3 = b
Step 4: Write the equation
After finding the value of b, we can now write the slope-intercept equation of the line with the given slope and point:
y = (-7/2)x + 3
Therefore, the slope-intercept equation for the line that passes through the point (2, -4) and has a slope of -7/2 is y = (-7/2)x + 3.