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December 19, 2014

December 19, 2014

Posted by **Josh** on Wednesday, August 3, 2011 at 6:01pm.

f(x)=-4x^2-32x+9

- Calculus -
**MathMate**, Wednesday, August 3, 2011 at 10:27pmThere are many "standard forms". One of which is f(x)=a(x-h)²+k

where (h,k) is the position of the vertex, and a is a constant.

This can be achieved by completing the square of

f(x)=-4x^2-32x+9

=-4(x²+8x-9/4)

=-4(x+4)²+4*4²+9/4

=-4(x+4)²+265/4

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