Posted by J.T on Wednesday, August 3, 2011 at 12:11pm.
..........PbCl2(s) ==> Pb^2+ + 2Cl^-
x = solubility..x.......x.......2x
Ksp = (Pb^2+)(Cl^-)^2
Ksp = (x)(2x)^2
Solve for x which will give you the moles/L of PbCl2.
Mols/L x 0.48 L = moles in 480 mL.
Then moles x molar mass PbCl2 = grams PbCl2.
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