Posted by ceasar1 on Wednesday, August 3, 2011 at 7:56am.
If the circle is tangent to both axes and passes through (-3,6), I see its centre to be in the 2nd quadrant.
If the radius is r, then its centre must be (-r,r) and its equation is
(x+r)^2 + (y-r)^2 = r^2
x^2 + 2rx + r^2 + y^2 - 2ry + r^2 = r^2
at (-3,6)
9 - 6r + r^2 + 36 - 12r = 0
r^2 - 18r + 45 = 0
(r-3)(r-15) = 0
r = 3 or r = 15
since you want the smaller circle ... r = 3
equation:
(x+3)^2 + (y-3)^2 = 9
Related Questions
math - can u help this the qustion is : A circle passes through the points (1,4...
steev - can u help this the qustion is : A circle passes through the points (1,4...
Math - I have a series of questions that I did. They lead up to the last ...
geometry - find the equation of the circle having center on 3x+y=6 and tangent ...
Math - Determine an equation of the circle that is tangent to both axes, has its...
maths - 1) Circle centre (7,-2) passes through (-2,10). Calculate radius and ...
Math (Pre Cal) - Hi, I am studying for a precalculus quiz and I do not ...
GEOMETRY INSCRIBED ANGLES MULTIPLE CHOICE QUESTION - segment BC is tangent to ...
Analytic Geometry - Give the equation of the circle tangent to both axes of ...
Alg2 - The tangent to a circle may be defined as the line that intersects the ...
For Further Reading
