A block of mass 2kg is pushed along a table with a constant velocity by a force of 5N.When the push is increased to 9N,what is a)the resultant force b)the acceleration
Resultant force= 4N
Acceleration= 2ms-2
i dnt know help
(a)Reforce
f2-f1
9N-5N=4N
Qb)Acceleration
*F=ma
*F/m=a
4/2=2
Thanks
I want to be helped in
Physics
A=4N
B=8N
Thanks its helpful
To find the resultant force and acceleration, we need to use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Let's break down the problem into two scenarios, when the force is 5N and 9N:
a) When the force is 5N:
- The mass of the block is given as 2kg.
- The force acting on the block is 5N.
- Since the block is pushed with a constant velocity, it means that there is no acceleration.
- Therefore, the resultant force is equal to the applied force, which is 5N.
b) When the force is increased to 9N:
- The mass of the block and the previous conditions remain the same.
- The force acting on the block is now 9N.
- To find the acceleration, we'll use Newton's second law: F = ma, where F is the resultant force, m is the mass, and a is the acceleration.
- Rearranging the formula: a = F / m, we can calculate the acceleration.
- Substituting the known values: a = 9N / 2kg = 4.5 m/s^2.
So, the answers are:
a) The resultant force is 5N when the force is 5N and 9N when the force is increased.
b) The acceleration is 0 m/s^2 when the force is 5N and 4.5 m/s^2 when the force is increased to 9N.