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March 29, 2017

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Given the quadraticf(x)=x^2-14x+49, find a value of x such thatf(x)=36

  • intermediate algebra - ,

    36 = x^2 -14 x + 49

    x^2 -14 x + 13 = 0

    (x-13)(x-1) = 0
    x = 13 or x = 1

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