Thursday

October 2, 2014

October 2, 2014

Posted by **Lisa** on Tuesday, August 2, 2011 at 8:10pm.

- math -
**Damon**, Tuesday, August 2, 2011 at 8:25pmPump 1 does (1/5) pool/day

pump 2 does (1/7) pool/day

together they do (1/5)+(1/7) pool/day

that is

7/35 + 5/35 = 12/35 pool/day

so it will take 35/12 = 2.92 days/pool

- math -
**Reiny**, Tuesday, August 2, 2011 at 8:26pmrate of 1st pump = pool/5

rate of 2nd pump = poo/7

combined rate = pool/5 + pool/7 = (12/35)pool

time at combined rate = pool / ((12/35)pool) = 35/12 or 2.916667

it will take about 2.92 hours or 2hrs, 55 minutes

- math -
**Lisa**, Tuesday, August 2, 2011 at 8:44pmthank you both

**Answer this Question**

**Related Questions**

math - One pump can empty a pool in 5 days, whereas a second pump can empty the ...

Math - One pump can empty a pool in 5 days, whereas a second pump can empty the ...

math - One pump can empty a pool in 5 days, whereas a second pump can empty the ...

math-algebra - one pump can empty a pool in 5 days, wheras a second pump can ...

college algebra - Pump A alone can empty the city pool in 12 hours. If only pump...

algebra - Pump A can fill a swimming pool in 6 hours and pump B can fill the ...

Math - The Timuga swimming pool, of Manila City has two pumps it uses to fill ...

Physics - 2. A pool has an area A = 50 m2 and depth h = 2.5 m. The pool is ...

Algebra I - Pump A, working alone, can fill a tank in 3 hours, and pump B can ...

math - If pump A and pump B work together, they can fill a pool in 4 hours. Pump...