Posted by **amanda** on Tuesday, August 2, 2011 at 5:01pm.

the diagonal of a rectangular room is 13ft long. one wall measures 7ft longer than the adjacent wall. what are the dimensions of the room

- algebra -
**I think**, Tuesday, August 2, 2011 at 7:10pm
13=(x+7)+x

x=3

So i think it would be 10X 3?

- algebra -
**Henry**, Tuesday, August 2, 2011 at 8:52pm
The diagonal forms 2 rt triangles: it is the hyp of the triangles.

Width = X ft.

Length = (x+7) ft.

x^2 + (x+7)^2 = (13)^2,

x^2 + x^2 + 14x + 49 = 169,

2x^2 + 14x - 120 = 0,

Divide both sides by 2:

x^2 + 7x - 60 = 0,

(x-5)(x+12) = 0,

x-5 = 0,

x = 5.

x+12 = 0,

x = -12.

Select + value of X:

X = 5 ft = Width.

X + 7 = 12 ft = Length.

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